4x^2/5/x^2/40

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Solution for 4x^2/5/x^2/40 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((4*x^2)/5)/(x^2))/40 = 0

1/50 = 0

x belongs to the empty set

x belongs to the empty set

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